Having trouble with simple XOR

[Donone]

I am having trouble converting to Lua. Can somebody please help with the following...
I have a value in a matrix which can be True or False.
I wish to XOR it with True, thus reversing it.

Alternatively value of 1 or 0 and XOR it with 1.

[CrowdAds]

[Brett_val]

To reverse booleans you can use not:

value = true
value = not value
print(value) --"false"

I'm not sure if lua has a XOR port.. I'd make it myself with a bunch of if statements:

function xor(x,y)
	if (x==y) then
	  return 0
	else
	  return 1
	end
end

if xor(1,0)==1 then print("yes") end --"yes"

hope this helps..

[Donone]

Thanks for the reply. The reverse in my instance cannot use Not because it must depend on the unknown value already existing. I appreciate the if statements but they do seem a very long winded-solution to what in other languages is a = b xor c.
I am surprised that it appears there is no such statement when there is And and Or
Thank you

[ThievingSix]

--[[---------------
LuaBit v0.4
-------------------
a bitwise operation lib for lua.

http://luaforge.net/projects/bit/

How to use:
-------------------
 bit.bnot(n) -- bitwise not (~n)
 bit.band(m, n) -- bitwise and (m & n)
 bit.bor(m, n) -- bitwise or (m | n)
 bit.bxor(m, n) -- bitwise xor (m ^ n)
 bit.brshift(n, bits) -- right shift (n >> bits)
 bit.blshift(n, bits) -- left shift (n << bits)
 bit.blogic_rshift(n, bits) -- logic right shift(zero fill >>>)
 
Please note that bit.brshift and bit.blshift only support number within
32 bits.

2 utility functions are provided too:
 bit.tobits(n) -- convert n into a bit table(which is a 1/0 sequence)
               -- high bits first
 bit.tonumb(bit_tbl) -- convert a bit table into a number 
-------------------

Under the MIT license.

copyright(c) 2006~2007 hanzhao (abrash_han*************)
--]]---------------

do

------------------------
-- bit lib implementions

local function check_int(n)
 -- checking not float
 if(n - math.floor(n) > 0) then
  error("trying to use bitwise operation on non-integer!")
 end
end

local function to_bits(n)
 check_int(n)
 if(n < 0) then
  -- negative
  return to_bits(bit.bnot(math.abs(n)) + 1)
 end
 -- to bits table
 local tbl = {}
 local cnt = 1
 while (n > 0) do
  local last = math.mod(n,2)
  if(last == 1) then
   tbl[cnt] = 1
  else
   tbl[cnt] = 0
  end
  n = (n-last)/2
  cnt = cnt + 1
 end

 return tbl
end

local function tbl_to_number(tbl)
 local n = table.getn(tbl)

 local rslt = 0
 local power = 1
 for i = 1, n do
  rslt = rslt + tbl[i]*power
  power = power*2
 end
 
 return rslt
end

local function expand(tbl_m, tbl_n)
 local big = {}
 local small = {}
 if(table.getn(tbl_m) > table.getn(tbl_n)) then
  big = tbl_m
  small = tbl_n
 else
  big = tbl_n
  small = tbl_m
 end
 -- expand small
 for i = table.getn(small) + 1, table.getn(big) do
  small[i] = 0
 end

end

local function bit_or(m, n)
 local tbl_m = to_bits(m)
 local tbl_n = to_bits(n)
 expand(tbl_m, tbl_n)

 local tbl = {}
 local rslt = math.max(table.getn(tbl_m), table.getn(tbl_n))
 for i = 1, rslt do
  if(tbl_m[i]== 0 and tbl_n[i] == 0) then
   tbl[i] = 0
  else
   tbl[i] = 1
  end
 end
 
 return tbl_to_number(tbl)
end

local function bit_and(m, n)
 local tbl_m = to_bits(m)
 local tbl_n = to_bits(n)
 expand(tbl_m, tbl_n) 

 local tbl = {}
 local rslt = math.max(table.getn(tbl_m), table.getn(tbl_n))
 for i = 1, rslt do
  if(tbl_m[i]== 0 or tbl_n[i] == 0) then
   tbl[i] = 0
  else
   tbl[i] = 1
  end
 end

 return tbl_to_number(tbl)
end

local function bit_not(n)
 
 local tbl = to_bits(n)
 local size = math.max(table.getn(tbl), 32)
 for i = 1, size do
  if(tbl[i] == 1) then 
   tbl[i] = 0
  else
   tbl[i] = 1
  end
 end
 return tbl_to_number(tbl)
end

local function bit_xor(m, n)
 local tbl_m = to_bits(m)
 local tbl_n = to_bits(n)
 expand(tbl_m, tbl_n) 

 local tbl = {}
 local rslt = math.max(table.getn(tbl_m), table.getn(tbl_n))
 for i = 1, rslt do
  if(tbl_m[i] ~= tbl_n[i]) then
   tbl[i] = 1
  else
   tbl[i] = 0
  end
 end
 
 --table.foreach(tbl, print)

 return tbl_to_number(tbl)
end

local function bit_rshift(n, bits)
 check_int(n)
 
 local high_bit = 0
 if(n < 0) then
  -- negative
  n = bit_not(math.abs(n)) + 1
  high_bit = 2147483648 -- 0x80000000
 end

 for i=1, bits do
  n = n/2
  n = bit_or(math.floor(n), high_bit)
 end
 return math.floor(n)
end

-- logic rightshift assures zero filling shift
local function bit_logic_rshift(n, bits)
 check_int(n)
 if(n < 0) then
  -- negative
  n = bit_not(math.abs(n)) + 1
 end
 for i=1, bits do
  n = n/2
 end
 return math.floor(n)
end

local function bit_lshift(n, bits)
 check_int(n)
 
 if(n < 0) then
  -- negative
  n = bit_not(math.abs(n)) + 1
 end

 for i=1, bits do
  n = n*2
 end
 return bit_and(n, 4294967295) -- 0xFFFFFFFF
end

local function bit_xor2(m, n)
 local rhs = bit_or(bit_not(m), bit_not(n))
 local lhs = bit_or(m, n)
 local rslt = bit_and(lhs, rhs)
 return rslt
end

--------------------
-- bit lib interface

bit = {
 -- bit operations
 bnot = bit_not,
 band = bit_and,
 bor  = bit_or,
 bxor = bit_xor,
 brshift = bit_rshift,
 blshift = bit_lshift,
 bxor2 = bit_xor2,
 blogic_rshift = bit_logic_rshift,

 -- utility func
 tobits = to_bits,
 tonumb = tbl_to_number,
}

end

--[[
for i = 1, 100 do
 for j = 1, 100 do
  if(bit.bxor(i, j) ~= bit.bxor2(i, j)) then
   error("bit.xor failed.")
  end
 end
end
--]]

[ZaPx64]

Xor could be faster using (a == ~b) I guess.

[Brett_val]

Originally Posted by ZaPx64

Xor could be faster using (a == ~b) I guess.

true, then it would just be one if else.

I don't really understand what Thievingsix posted..

[Donone]

Thank you all for the response, I guess Not is pretty good after all.
I guess Thievingsix posted a library which happens to includes the function bit_xor(m,n).

[ThievingSix]

If your doing real bitwise operations with numbers, (a == ~b) just won't cut it..